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5t^2-100t=45
We move all terms to the left:
5t^2-100t-(45)=0
a = 5; b = -100; c = -45;
Δ = b2-4ac
Δ = -1002-4·5·(-45)
Δ = 10900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10900}=\sqrt{100*109}=\sqrt{100}*\sqrt{109}=10\sqrt{109}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-10\sqrt{109}}{2*5}=\frac{100-10\sqrt{109}}{10} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+10\sqrt{109}}{2*5}=\frac{100+10\sqrt{109}}{10} $
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